0=9x^2+18-3

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Solution for 0=9x^2+18-3 equation: 



0=9x^2+18-3

We move all terms to the left:

0-(9x^2+18-3)=0

We add all the numbers together, and all the variables

-(9x^2+18-3)=0

We get rid of parentheses

-9x^2-18+3=0

We add all the numbers together, and all the variables

-9x^2-15=0

a = -9; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·(-9)·(-15)
Δ = -540
Delta is less than zero, so there is no solution for the equation

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